Linux实现模拟多进程并发执行
示例：
#!/bin/bash
for((i=0;i<5;i++))
do
{
sleep 1; echo "$i--">>aa && echo "done"
}&
done
wait
cat aa | wc -l
rm aa
解析 &代表并发执行，wait等待前面执行完了再执行，例如此示例中，如果没有wait很可能还没创建aa文件
Linux下的中断
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
int main(void)
{
pid_t pid; //pid
printf("Before fork...
");
switch( pid = fork()) {
case -1:
printf("fork call fail
");
fflush(stdout);
exit(1);
case 0:
printf("child call
");
printf("the pid of child is %d
", getpid());
printf("the pid of child's parent is %d
", getppid());
printf("child exiting...
");
exit(0);
default:
printf("this is a father
");
printf("the pid of parent is %d
", getpid());
printf("the pid of child is %d
", pid);
}
printf("After fork, programing exiting
");
exit(0);
}